12 SQL Developer Interview Questions and Answers

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What is a Relational Database Management System (RDBMS), and which one are you most familiar with?

A RDBMS is a system that organizes data into tables called relations, which are further organized into columns (fields) and rows (often called tuples). The relational model allows data to be queried in a nearly unlimited number of ways, making it great for sorting through large volumes of data. It’s important to pick a SQL developer who’s experienced with the particular set of web technologies you plan to use to support your app. Common SQL dialects include PL/SQL for Oracle, T-SQL for MS SQL, and JET SQL for MS Access. Look up any particular dialects used for your chosen RDBMS.

What are the standard SQL commands every SQL developer should know?

The basic SQL commands can be organized into the following categories:

  • Data Manipulation Language (DML)
    • INSERT: Creates records. The “Create” in CRUD.
    • SELECT: Retrieves records. The “Read” in CRUD.
    • UPDATE: Modifies records. The “Update” in CRUD.
    • DELETE: Deletes records. The “Delete” in CRUD.
  • Data Definition Language (DDL)
    • CREATE: Creates a new object.
    • ALTER: Alters an existing object.
    • DROP: Deletes an existing object.
  • Data Control Language: (DCL)
    • GRANT: Grants privileges to users.
    • REVOKE: Revokes privileges previously granted to a user.

In practice however, you should be aware that your typical developer is most likely going to answer this question with CRUD (Create, Read, Update, and Delete), the four essential database operations for database manipulation. Bonus points if they also mention some of the others.

Can you explain how a RDBMS organizes data into tables and fields?

A table is composed of columns (fields) and rows (records or tuples). Each record can be considered as an individual entry that exists within the table and contains multiple fields. For example, a data entry (record) for a customer might consist of the fields: ID, name, address, and purchase.

What is a NULL value and how does it differ from a zero value?

The easiest way to explain this difference is to recognize that zero is a value representing the number zero. NULL is a non-value or a placeholder for data that is not currently known or specified. The result of any operation on a NULL value, as in arithmetic, will be undefined.

What are SQL Constraints?

Constraints are rules you can place on columns or tables to limit the type of data that can be entered into a table. This prevents errors and can improve the accuracy and reliability of the database as a whole. Common constraints include:

  • NOT NULL: Prevents a column from having a NULL value.
  • DEFAULT: Specifies a default value for a column where none is specified.
  • PRIMARY KEY: Uniquely identifies rows/records within a database table.
  • FOREIGN KEY: Uniquely identifies rows/records from external database tables.
  • UNIQUE: Ensures all values are unique.
  • CHECK: Checks values within a column against certain conditions.
  • INDEX: Quickly creates and retrieves data from a database.

Name four ways to maintain data integrity within a RDBMS.

When it comes to storing data accurately, consistently, and reliably within a RDBMS, there are four general types of data integrity that you can implement:

  • Entity (Row) Integrity: Avoids duplicate rows in tables.
  • Domain (Column) Integrity: Restricts the type, format, or range of values to enforce valid entries.
  • Referential Integrity: Ensures rows used by other records cannot be deleted.
  • User-Defined Integrity: Enforces rules set by the user that do not fall into the other categories.

What is the purpose of database normalization and how does it work?

The primary purpose of normalization is to make databases more efficient by eliminating redundant data and ensuring data dependencies are coherent. Storing data logically and efficiently reduces the amount of space the database takes up and improves performance. The set of guidelines used to achieve normalization are called normal forms, numbered from 1NF to 5NF. A form can be thought of as a best-practice format for laying out data within a database.

Explain the difference between an inner join and outer join using an example.

An inner join is when you combine rows from two tables and create a result set based on the predicate, or joining condition. The inner join only returns rows when it finds a match in both tables. An outer join will also return unmatched rows from one table if it is a single outer join, or both tables if it is a full outer join. A solid example of this will clearly illustrate the difference and demonstrate how well the developer understands joins.

What is wrong with the SQL query below?

SELECT UserId, AVG(Total) AS AvgOrderTotal
FROM Invoices
HAVING COUNT(OrderId) >= 1

The issue here is that there must be a GROUP BY clause here. This query will get the average order amount by customer (UserId) where the customer has at least 1 order. The correct query is listed below:

SELECT UserId, AVG(Total) AS AvgOrderTotal
FROM Invoices
GROUP BY Userid
HAVING COUNT(OrderId) >= 1

Consider the two tables below. Write a query that retrieves all employees recruited by John Do. How would you write a second query to retrieve all employees that were not recruited by any recruiter?

Employee Table

Id Name RecruitedBy
1 Jean Grayson NULL
2 Paul Smith 1
3 John Do NULL
4 Alex Lee 3
5 Lisa Kim 3
6 Bob Thompson NULL

Recruiter Table

Id Name
1 Bob Smith
2 Paul Allen
3 John Do

The following query will retrieve all recruiters recruited by John Do. SELECT Employee.

Name FROM Employee
JOIN Recruiter ON Employee.RecruitedBy = Recruiter.Id
WHERE RecruitedBy = 3

To retrieve all employees who were not recruited by anyone in the recruiter table, you could use the following query:

SELECT Employee.Name FROM Employee
JOIN Recruiter ON Employee.RecruitedBy = Recruiter.Id
WHERE RecruitedBy Is Null

Write a SQL query to find the 10th tallest peak (“Elevation”) from a “Mountain” table. Assume that there are at least 10 records in the Mountain table. Explain your answer.

This can be accomplished using the “TOP” keyword as follows.

SELECT TOP (1) Elevation FROM
(
  SELECT DISTINCT TOP (10) Elevation FROM Mountain ORDER BY Elevation DESC
) AS Mt ORDER BY Elevation

The first query takes the top 10 mountains by elevation in the table and lists them in descending order, with the tallest mountain at the top of the list. However, since we want the 10th tallest mountain, the second query, “ AS Mount ORDER BY Elevation”, promptly reorders the list of 10 in ascending order before the top record is selected. Note that not all databases support the “TOP” keyword, so answers may vary. Another possible solution that follows a similar logic for MySQL or PostreSQL is detailed below, this time using the “LIMIT” keyword.

SELECT Elevation FROM
(
  SELECT DISTINCT Elevation FROM Mountain ORDER BY Elevation DESC LIMIT 10
) AS Mt ORDER BY Elevation LIMIT 1;

Given two tables created in the code block below, how would you write a query to fetch values in table “fibonacci” that are not in table “prime” without using the “NOT” keyword? Can you name a database technology where this is not possible?

create table fibonacci(id numeric);
create table prime(id numeric);

insert into fibonacci(id) values
    (2),
    (3),
    (5),
    (8),
    (13),
    (21);

insert into prime(id) values
    (2),
    (3),
    (5),
    (13);

SQLite, PostgreSQL, and SQL Server all support the ever useful “except” keyword which can be employed as detailed below

select * from fibonacci
except
select * from prime;

A popular database technology that does not support “except” is MySQL, which is why it must use the “not in” keyword. Note that for Oracle, the “minus” keyword must be used instead.

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  • $40 hourly
    Rommelie L.
    • 5.0
    • (23 jobs)
    Manila, METRO MANILA
    Featured Skill SQL
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    👋 Hello, dear client. Thanks for visiting my profile. I’m an AI/ML Engineer and Full-Stack Developer who helps startups and businesses build AI-driven, scalable, and production-ready solutions. I combine deep knowledge in machine learning, GenAI, and web app development to deliver fast, reliable, and measurable results. With my rich experience in AI and fullstack field built in my professional career, I'd like to provide innovative solutions that attribute success to crazy ideas and learn the ropes from it. ⚙️ Core Expertise 🤖 Artificial Intelligence / Machine Learning • Python, TensorFlow, PyTorch, Scikit-learn, XGBoost, Transformers • Model design: time-series forecasting, sentiment analysis, recommendation engines, fraud detection 🚀 Generative AI & LLM Solutions • GPT, Llama, Gemini, Claude, BERT • RAG pipelines, Fine-tuning, Prompt Engineering • Vector Databases: Pinecone, FAISS, Weaviate • Custom Chatbots, AI Agents, Conversational Apps 💻 Full-Stack Web Development • Frontend: React, Next.js, Vue, Angular, TypeScript, Tailwind CSS • Backend: FastAPI, Node.js, PHP, Flask, Go, REST & GraphQL APIs • Databases: MySQL, PostgreSQL, MongoDB, Supabase, Firebase 🗜 Automation & Integration • n8n, Make, Zapier, Vapi • Business workflow automation and AI integration 🔧 DevOps & Cloud • Docker, AWS, GCP, CI/CD (GitHub Actions), Microservices, Scalability Optimization 💡 What I Can Build for You ✅ Custom ML models for predictions and insights ✅ LLM-powered chatbots or internal assistants ✅ AI agents connected to live data sources ✅ RAG-based knowledge retrieval systems ✅ Automated workflows for repetitive business tasks ✅ Full-stack AI SaaS platforms (React + FastAPI/Node) ✅ End-to-end deployment on AWS/GCP 🌟 Why Clients Choose Me • Strong background in both AI research and software engineering • Clean, modular, and scalable code following best practices • Clear communication and rapid delivery • Proven track record of building production-ready AI systems If you’re looking for a reliable AI/Full-Stack engineer who delivers both technical excellence and business impact, let’s connect. I’ll help you go from concept → prototype → production smoothly and efficiently.
  • $35 hourly
    Muhammad H.
    • 5.0
    • (13 jobs)
    Hyderabad, SD
    Featured Skill SQL
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  • $30 hourly
    Aaron A.
    • 4.8
    • (15 jobs)
    Accra, GREATER ACCRA
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